Re: Interpretation of DW_AT_external

[Sami Wagiaalla <swagiaal at redhat dot com>]

> While GCC does use a somewhat different convention for DW_AT_external than
> other compilers, this seems clearly correct; A::a is a globally
> visible name.  Why shouldn't 'a' be found in the global scope?  Or do
> you mean that 'a' with no 'A::' is found?

Yes I meant 'a' without 'A::', but it looks like that is not found. 
Which is the correct behaviour.

However, I am trying to construct a kind of "block" object from 
namespaces so that cp_lookup_symbol_namespace can look inside them 
instead of concatenating the expression elements and doing a global 
search. And that function ends up putting the variable in the global 
scope instead of my object.

> The name in GDB's symbol table will be "A::a".

Is this because the linkage_name is used ?.. I am trying to not depend 
on linkage_name. There are situations where A::a is visible as just a, 
or if it was enclosed in another namespace B it would be B::A::a.

Btw I should have mention on this earlier on this list but I am 
investigation test failures that I am getting with the namespace test in 
gdb test suit.

Thanks,
  Sami