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RE: [PATCH] x86: suppress emission of zero displacements in memoryoperands


On 14 July 2006 18:31, H. J. Lu wrote:

> On Fri, Jul 14, 2006 at 11:03:38AM -0600, Clifford T. Matthews wrote:
>> Howdy,
>> 
>> I'm a little over a year late to the discussion, but it was only
>> yesterday that I figured out that I was being bitten by a change that was
>> made in May of 2005. 
>> 
>> Syn68k is software (written by Mat Hostetter) that dynamically
>> translates 68k assembly to x86 assembly.  It doesn't want to invoke a
>> full-blown assembler as it does its work, so instead, at build time,
>> it uses gas to compile a whole bunch of templates and figure out the
>> significance of the bits that get created.
>> 
>> Starting with binutils-2.16.90.0.3, instructions like
>> 
>>     lea 0x0(%eax),%eax
>> 
>> began compiling into the exact same byte sequence as
>> 
>>     lea (%eax),%eax
>> 
> 
> I have been thinking to use 0x0B, 0x0W, 0x0L to indicate the size
> of displacements.
> 

  That would be useful.  However, 0x0B is a valid hex number!  How about using
the same syntax as m68k, where you'd say 0x0.b, 0x0.w or 0x0.l ?

    cheers,
      DaveK
-- 
Can't think of a witty .sigline today....


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