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RE: Starting Programms in the background
- To: <cygwin at sources dot redhat dot com>
- Subject: RE: Starting Programms in the background
- From: "Jeff Hu" <max at huville dot com>
- Date: Thu, 2 Nov 2000 19:46:36 -0500
I think this is related to how bash is started. If you:
1) start a dos box window
2) start bash
3) start notepad in the background
4) exit bash
5) exit the dos prompt window
the dos box remains until you exit notepad.
Jeff
-----Original Message-----
From: cygwin-owner@sources.redhat.com
[mailto:cygwin-owner@sources.redhat.com]On Behalf Of Christopher Faylor
Sent: Thursday, November 02, 2000 3:20 PM
To: cygwin@sources.redhat.com
Subject: Re: Starting Programms in the background
On Thu, Nov 02, 2000 at 11:58:01AM -0800, Earnie Boyd wrote:
>--- Christopher Faylor <cgf@redhat.com> wrote:
>> On Thu, Nov 02, 2000 at 06:10:07AM +0100, klaus.berndl@sdm.de wrote:
>> >If i start a program in the background from bash (e.g. "winword.exe
>> ><document> &") then all is working fine. But if i try to exit from the
>> >bash-shell from which i have started the program before i have finished
>> >the program then bash writes "logout" but doesn?t terminate until i
>> >terminate all previous started programs.
>> >
>> >How can this be avoided, means how to exit bash regardless of any still
>> >running background programs?
>>
>> The only time this should happen is when you are using CYGWIN=tty. In
this
>> case, the main process (bash) "owns" the tty and can't exit until every
>> child which is using the tty has exited. The only way around this is to
>> not use CYGWIN=tty.
>>
>
>Then it's broken. I assume notty is still the default, correct? Then the
>window refuses to close until I exit the process. This is with
1.1.6(0.29/3/2)
>build.
Feel free to debug it. This exits for me on Windows NT.
cgf
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