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RE: Varibles not working in do loop...
On 03 April 2007 15:07, Kevin Markle wrote:
> Larry Hall (Cygwin) formulated on Monday :
>> Andrew Louie wrote:
>>> On 4/2/07, Kevin Markle wrote:
>>>> Larry Hall (Cygwin) expressed precisely :
>>>>> Kevin Markle wrote:
>>>
>>>> What does this mean please and or would you send me your copy that works
>>>> fine? "$LOG" == > "". In these cases, the "hang" is 'cat' waiting for
>>>> input from the command
>>>>> line.
>>>
>>> I think he means that in the line:
>>>
>>>> UPDATES_NEEDED=`cat $LOG | grep "updates detected" | tail -1`
>>>
>>> cat $LOG... will hang if $LOG == "" because "cat" is waiting for input.
>>>
>>
>> Precisely.
>
> That helps but my problem is the line above where it get the value for
> LOG for whatever reason doesn't get the value of LOG in the for loop
> but can outside of the loop... :o)
You mean this line?
LOG=`ls -al $DIR | grep $t | grep WINDOWS`
You're listing the contents of the directory, trying to find the one line
that contains the name of the file ($t) you're currently considering. Then
you're using grep a second time to only select (from that one line) any lines
that contain the text 'WINDOWS'. Presumably none of the files in
1group_1a_dev_clientlist.out have the word "WINDOWS" in their name.
What are you *trying* to do with that second grep?
cheers,
DaveK
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