From: 越 王 <wangyue0921@yahoo.com.cn>
To: ecos-discuss@ecos.sourceware.org
Subject: [ECOS] how redboot get the parameter passed from its command?
Date: Mon, 16 Apr 2007 09:52:15 +0800 (CST)
Hi,all
I want to add a new command to redboot,but i don't
understand how redboot commands carry out?
for exemple, the file iomem.c shows
RedBoot_cmd("iopeek", //the command
iopeek declare here
"Read I/O location",
"[-b <location>] [-1|2|4]",
do_iopeek
);
void
//carry out this command
do_iopeek(int argc, char *argv[])
{
struct option_info opts[4]; //the struct
option_info declared in redboot.h?
unsigned long base;
bool base_set;
bool set_32bit = false;
bool set_16bit = false;
bool set_8bit = false;
int size = 1, value;
init_opts(&opts[0], 'b', true,
OPTION_ARG_TYPE_NUM, &base,
&base_set, "base address");
init_opts(&opts[1], '4', false,
OPTION_ARG_TYPE_FLG,
&set_32bit, 0, "output 32 bit units");
init_opts(&opts[2], '2', false,
OPTION_ARG_TYPE_FLG,
&set_16bit, 0, "output 16 bit units");
init_opts(&opts[3], '1', false,
OPTION_ARG_TYPE_FLG,
&set_8bit, 0, "output 8 bit units");
if (!scan_opts(argc, argv, 1, opts, 4, 0, 0, ""))
{
return;
}
if (!base_set) {
diag_printf("iopeek what <location>?\n");
return;
}
if (set_32bit) {
size = 4;
} else if (set_16bit) {
size = 2;
} else if (set_8bit) {
size = 1;
}
switch (size) {
case 4:
HAL_READ_UINT32 ( base, value );
diag_printf("0x%04lx = 0x%08x\n", base, value
);
break;
case 2:
HAL_READ_UINT16 ( base, value );
diag_printf("0x%04lx = 0x%04x\n", base, value
);
break;
case 1:
HAL_READ_UINT8 ( base, value );
diag_printf("0x%04lx = 0x%02x\n", base, value
);
break;
}
}
My question is how redboot get the parameter passed
from the command iopeek to some function that realize
the command? I guess the init_opts did it.But how it
works? And I serched the redboot.h and
cyg/hal/hal_io.h,can't find the definition of this
function.