[Bug python/12520] cannot parse function types as templateparameters

["zilla at kayari dot org" <sourceware-bugzilla at sourceware dot org>]

http://sourceware.org/bugzilla/show_bug.cgi?id=12520

--- Comment #1 from Jonathan Wakely <zilla at kayari dot org> 2011-02-25 17:31:29 UTC ---
I applied Ian's change to the copy of libiberty/cp_demangle.c in the gdb-7.2
sources, rebuilt, and tried again. That causes the correct type to be displayed
for the second example:

RuntimeError: No type named int ().

But it doesn't prevent the error.

It makes no difference to the first example:

RuntimeError: syntax error, near `)>, std::less<int>, std::allocator<st'

So http://gcc.gnu.org/PR46332 doesn't change anything, GDB still can't
pretty-print templates involving function types.

The "No type named int ()" error is curious, because the container's value_type
is "int(*)()" so I don't know what it's doing looking up "int()" anyway.

Here's a slightly simpler example using <vector> not <map>, and showing both
problems:

#include <vector>

template<typename Callable> struct function { };

int main()
{
    typedef function<int()> func_type;
    std::vector<func_type> m;

    typedef int(*funcptr_type)();
    std::vector<funcptr_type> m2;

    return 0;
}

Neither 'm' nor 'm2' can be pretty-printed

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