[Bug c++/14248] New: Unable to call a templated member function inC++

["thor at math dot tu-berlin.de" <sourceware-bugzilla at sourceware dot org>]

http://sourceware.org/bugzilla/show_bug.cgi?id=14248

             Bug #: 14248
           Summary: Unable to call a templated member function in C++
           Product: gdb
           Version: HEAD
            Status: NEW
          Severity: normal
          Priority: P2
         Component: c++
        AssignedTo: unassigned@sourceware.org
        ReportedBy: thor@math.tu-berlin.de
    Classification: Unclassified
              Host: x86_64-linux-gnu
            Target: x86_64-linux-gnu
             Build: x86_64-linux-gnu


If a class contains templated member functions, these member functions are
found by gdb and are printed, but cannot be called.

Consider the following class:

class OpenCLBuffer {
  //
  // more stuff here...
  //
public:
  template<typename type> type Peek(unsigned int offset);
};

plus a proper implementation. For the sake of the argument, assume:

template<typename type>
type OpenCLBuffer::Peek(unsigned int offset)
{
return 0;
}
template unsigned char OpenCLBuffer::Peek<unsigned char>(unsigned int);

Using the TAB expansion of gdb shows that this method is actually known to gdb:

p OpenCLBuffer::Peek<un[TAB]

shows (amonst others):

unsigned char OpenCLBuffer::Peek<unsigned char>(unsigned int)

You can even show its address:

(gdb) p OpenCLBuffer::Peek<unsigned char>
$2 = {unsigned char (OpenCLBuffer * const, unsigned int)} 0x76e5be
<OpenCLBuffer::Peek<unsigned char>(unsigned int)>

However, trying to call it from gdb gives nothing:

(gdb) call m_pBuffer[0]->Peek<unsigned char>(0)
Couldn't find method OpenCLBuffer::Peek<unsigned char>

Bummer!

This is version 7.4.1 of gdb. Potentially, this is a duplicate of bug 9423, a
regression from a very old version of gdb.

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