Re: gdb seg violation during print command

[Daniel Berlin <dan at cgsoftware dot com>]

And i don't
Breakpoint 1, main () at a.c:11
11        cout << "1\n";
Current language:  auto; currently c++
(gdb) p tt
tt               tteesstt11(int)  ttyname
(gdb) p tteesstt11(1)
------ Arg is int [7], parm is int [7]
Overloaded function instance tteesstt11(int) # of parms 1
...Badness @ 0 : 0
...Badness @ 1 : 0
Overload resolution champion is 0, ambiguous? 0

$1 = 4
(gdb)                


I can almost guarantee this is not a gdb bug.
Compiled with both dwarf2 debug info, and stabs debug info, it works fine
on BeOS and linux.

On Thu, 4 May 2000, David Cogen wrote:

> > Try adding a line or three to main that do nothing.
> 
> Like this?
> 
> #include <iostream>
> 
> int tteesstt11 (int)
> {
>   cerr << "\n";
>   return 4;
> }
> 
> int main ()
> {
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
>   cout << "1\n";
> }
> 
> 
> I set my break on the first cout in main. When I print tteesstt11(1) I still
> get the debugger seg violation.
> 
> -- DavidC
>