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Re: scope in nested function

From: Bill Pursell <bill dot pursell at gmail dot com>
To: Jim Blandy <jimb at red-bean dot com>
Cc: gdb at sourceware dot org
Date: Fri, 31 Mar 2006 07:37:58 +0100
Subject: Re: scope in nested function
References: <442CC4BB.5070709@gmail.com> <8f2776cb0603302257t14f38361ibf8ab1cb74dfb774@mail.gmail.com>

Jim Blandy wrote:

On 3/30/06, Bill Pursell <bill.pursell@gmail.com> wrote:
I'm not sure how to reference a variable in a nested function from gdb.
In the gdb session below, there are 2 things I don't understand
how to do:
1) how do I set a breakpoint in foo? (other than by referencing a line
       number)
Have you tried calling it main::foo?

2) when I'm in foo, how do I reference i?

Have you tried calling it main::i?

I'm not sure these will work, but I think they're supposed to.


I get the error:
Can't find member of namespace, class, struct, or union named "main::foo"

Same for main::i

References:
- scope in nested function
  - From: Bill Pursell
- Re: scope in nested function
  - From: Jim Blandy

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