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Re: How to show the file being executed?
On Saturday 2010-02-20 07:37:22 -0500, Alfred M. Szmidt wrote:
> (gdb) info target
> Symbols from "/home/stefano/src/PROGRAM".
> Unix child process:
> Using the running image of child Thread 0xb5f33b70 (LWP 8998).
> While running this, GDB does not access memory from...
> Local exec file:
> `/home/stefano/src/PROGRAM', file type elf32-i386.
> Entry point: 0x804bc70
> 0x08048134 - 0x08048147 is .interp
> 0x08048148 - 0x08048168 is .note.ABI-tag
> 0x08048168 - 0x0804818c is .note.gnu.build-id
> [...]
>
> There is some way to show *only* this information?, otherwise I suggest
> to implement a show file command.
>
> You can use readelf to get most of that information.
I want to show *only* the local exec file as specified by the "file"
command, and within a gdb script, currently the only way I see is to
use info target.
Regards.