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Re: Can realloc be marked as a mallloc-like function?
On Mon, Jul 16, 2007 at 02:39:39PM -0000, Wolfram Gloger wrote:
> > int *p;
> > p = malloc (4);
> > *p = 0;
> > p = realloc (p, 4);
> > *p = 1;
>
> By that reasoning, consider:
>
> int *p;
> p = malloc (4);
> *p = 0;
> free(p);
> p = malloc (4);
> *p = 1;
Except that in the first sequence, the value of *p is retained across
the reallocation, so "*p = 0" is not dead. The two examples aren't
really the same at all.
r~