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Re: xsl:if question
- To: xsl-list at mulberrytech dot com
- Subject: Re: xsl:if question
- From: David Carlisle <davidc at nag dot co dot uk>
- Date: Fri, 7 Apr 2000 08:50:59 +0100 (BST)
- References: <003601bfa064$1a904720$09881f18@maine.rr.com>
- Reply-To: xsl-list at mulberrytech dot com
delete your { } they should generate a syntax error from your xpath
parser, although apparently don't on your system.
test="/foo/bar != /foo/cow">
is syntactically correct, but might not be what you want. Using != one
node sets almost never gives what anyone ever wants. I try to avoid
using != at all. If there are more than one bar or crow element
then the above will be true if _any_ bar is not equal to _any_ cow.
compare with
test="not(/foo/bar = /foo/cow)">
which is true if there is no bar which is equal to cow
David
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