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RE: order-by ... numbers
- To: "'xsl-list at mulberrytech dot com'" <xsl-list at mulberrytech dot com>
- Subject: RE: order-by ... numbers
- From: Brian Young <Brian dot Young at sas dot com>
- Date: Mon, 24 Jul 2000 14:21:29 -0400
- Reply-To: xsl-list at mulberrytech dot com
Hello,
You could try:
<xsl:for-each select="parade/personaggio">
<xsl:sort select="@punteggio" data-type="number" order="ascending" />
...
</xsl:for-each>
Thanks,
Brian Young
-----Original Message-----
From: Claudio Lo Piccolo [mailto:lopi-out@katamail.com]
Sent: Monday, July 24, 2000 1:34 PM
To: XSL-List@mulberrytech.com
Subject: order-by ... numbers
Hi, the xsl below:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl">
<xsl:template match="/">
...
<xsl:for-each select="parade/personaggio" order-by="@punteggio">
...
</xsl:for-each>
...
</xsl:template>
</xsl:stylesheet>
seems to sort items alphabetically, instead of numerically, as desired (say 14 stays before 2)
here is the xml:
<parade>
<personaggio punteggio="14">
...
</personaggio>
<personaggio punteggio="2">
...
</personaggio>
...
</parade>
Can somebody help me, please?
Bye, lopi
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