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Re: select following-siblings, but not all of them
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] select following-siblings, but not all of them
- From: Fred Boon <fredboon at yahoo dot com>
- Date: Tue, 19 Dec 2000 07:08:19 -0800 (PST)
- Reply-To: xsl-list at lists dot mulberrytech dot com
Francis,
your example code helped me flesh out the suggestions
yesterday of Ken Meltsner in his reply to my "creating
XML hierarchy where not existed before??" post.
thank you one, thank you all.
//F
--- Francis Norton <francis@redrice.com> wrote:
>
> use the following transform:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> <xsl:output method="text" version="1.0"
> indent="yes"/>
> <xsl:template match="/">
> <xsl:for-each select="/dataset/name">
> <xsl:variable name="key" select="."/>
> <xsl:value-of select="concat(., ' ')"/>
> <!-- get all following remark elements for
> which this is the
> nearest preceding name -->
> <xsl:for-each
>
select="following-sibling::remark[count(preceding-sibling::name[1]
> |
> $key) = 1]">
> <xsl:value-of select="concat(., ' ')"/>
> </xsl:for-each>
> </xsl:for-each>
> </xsl:template>
> </xsl:stylesheet>
>
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