Re: [xsl] Newbie document() question

[David Carlisle <davidc at nag dot co dot uk>]

> <xsl:variable name='otherDoc' select='document(MyXml.xml)'/>

MyXml.xml is a valid QName so will be evaluated to return all the
<myXML.xml> element nodes that are children of the root of
document a.

This is most likely empty, and anyway isn't what you want:-)


<xsl:variable name='otherDoc' select='document("MyXml.xml")'/>

is closer, but you don't really need a variable at all.

All you need do is copy the identity transformation from the XSL spec
and then add one extra template

<xsl:template match="some-xpath-that-matches-where-you-want-to-graft">
 <xsl:copy-of select='document('MyXml.xml')"/>
</xsl:template>


David

_____________________________________________________________________
This message has been checked for all known viruses by Star Internet delivered
through the MessageLabs Virus Control Centre. For further information visit
http://www.star.net.uk/stats.asp

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list