Re: [xsl] Position() of parent node

[Robert Koberg <rob at koberg dot com>]

When you match the parent set up a param that holds it's position.  Then
send that to the child's match where you accept the param.


----- Original Message -----
From: "Simon Cansick" <SC@access-accounts.com>
To: <xsl-list@lists.mulberrytech.com>
Sent: Tuesday, February 06, 2001 10:09 AM
Subject: [xsl] Position() of parent node


> Can anyone provide me with the syntax for getting the position() value of
> the current nodes' parent node (and the parent parent etc. position()
> value).  I seem only able to return the current position().
>
> I need to use the value in my generated HTML, not for template selection.
>
>
> Thanks for any help.
>
> Simon Cansick
> sc@access-accounts.com
>
> Access Accounting Ltd
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