[xsl] Dillemma when creating an XSL template ... how do I do this?

["JoshMEagle" <josh dot miller at eagletgi dot com>]

In the code snippet below, the <email> and <url> elements are inside the
<contact> element, and I want to display these as HTML links, any ideas how
I can accomplish this? The way it is below doesn't work.


<xsl:template match="contact">
  <p>
   <xsl:value-of select="name"/><br/>
   <xsl:value-of select="address"/>
   <xsl:value-of select="city"/>, <xsl:value-of select="state"/>
<xsl:value-of select="zip"/><br/>
   ph.<xsl:value-of select="phone"/><br/>
   fax.<xsl:value-of select="fax"/><br/>

   <xsl:template match="email">
        <a>
           <xsl:attribute name="href"><xsl:value-of select="."
/></xsl:attribute>
           <xsl:text><xsl:value-of select="." /></xsl:text>
        </a>
   </xsl:template>

   <xsl:template match="url">
        <a>
           <xsl:attribute name="href"><xsl:value-of select="."
/></xsl:attribute>
           <xsl:text><xsl:value-of select="." /></xsl:text>
        </a>
   </xsl:template>

  </p>
 </xsl:template>



Joshua Miller
Web Development
Eagle Technologies Group, Inc.
Business Solutions for the Next Generation
www.eagletgi.com
josh.miller@eagletgi.com


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