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Re: XSL rule for sorting the elements in descending order and display ing the first element in sorted list
- To: "Awasthi, Anand" <Anand_Awasthi at bmc dot com>
- Subject: Re: [xsl] XSL rule for sorting the elements in descending order and display ing the first element in sorted list
- From: Jeni Tennison <mail at jenitennison dot com>
- Date: Thu, 15 Feb 2001 09:29:49 +0000
- CC: "'xsl-list at lists dot mulberrytech dot com'" <xsl-list at lists dot mulberrytech dot com>
- Organization: Jeni Tennison Consulting Ltd
- References: <3DAC9CD31458D411BCE700D0B75D0A13E249AC@ES09-HOU.bmc.com>
- Reply-To: xsl-list at lists dot mulberrytech dot com
Hi Anand,
> i wanto to sort it in descending order and display the first element after
> sorting ...
i.e. to output the maximum of the list.
To sort you need the xsl:sort element. The xsl:sort element has to go
within something that iterates over a node set, such as an
xsl:for-each.
To select the first item, you need an xsl:if. You can test the
position() of the item in the node list. If it's equal to 1 then it's
the first item.
Putting that together, you get:
<xsl:template match="JartaXmlReport">
<xsl:for-each select="SessionStartupTime">
<xsl:sort data-type="number" order="descending" />
<xsl:if test="position() = 1">
<xsl:value-of select="." />
</xsl:if>
</xs:for-each>
</xsl:template>
I hope that helps,
Jeni
---
Jeni Tennison
http://www.jenitennison.com/
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