Re: [xsl] divide info in several output files

[cutlass <cutlass at secure0 dot com>]

>  need to output a html with a few (10 i.e.) of this itens
> and a link to other page containing the next 10 and
> so on til the last page including the last 8 items.
> 
> The quantity of items can be different from one xml file
> to another so no quantity-dependant-solution  
> 
other half of question, sorry hit send button too early.

if u pass the style sheet parameters as discussed in previous posting, u 
can always use just one xml file with all the articles, selectively 
displaying whatever range ( start and end / page).

u can do some counting math to generate < a hrefs > with param passed in 
the url ( remember parameter passing may be dependant on the type of 
parser you are using)

ex.

<a href="whatever.com?start=1&end=9>back</a>
<a href="whatever.com?start=20&end=29>next</a>

or depending on how your xml file was arranged

<a href="whatever.com?page=1>back</a>
<a href="whatever.com?page3>next</a>

as xsl allows you to do numbering and counting and such, i leave it to u 
to generate. once again there are stacks of other ways to do this, using 
xlink comes to mind ( then generate javascript or typical links with 
another stylesheet, etc ), this is just a humble start.

cheers, jim


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