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RE: sorting question
- To: <xsl-list at lists dot mulberrytech dot com>
- Subject: RE: [xsl] sorting question
- From: "Michael Kay" <mhkay at iclway dot co dot uk>
- Date: Wed, 7 Mar 2001 21:10:49 -0000
- Reply-To: xsl-list at lists dot mulberrytech dot com
> I'm trying to transform a list of elements into a sorted set
> of pairs, and
> haven't
> been able to determine how to get the 'next' sorted element
> relative to the current position.
This definitely calls for a two-pass approach, one to sort the data and the
second to group it.
>
> I checked out the xsl faq, and I found a posting of
> Jeni's that showed how to copy a sorted list into a variable, but
> it doesn't seem to be working for me.
> (I'm using MSXML3 in case that matters...)
>
> <xsl:variable name="letterlist">
> <xsl:for-each select="/ALPHABET/LETTER">
> <xsl:sort select="." />
> <xsl:copy-of select="." />
> </xsl:for-each>
> </xsl:variable>
>
> <!-- nothing comes out... -->
> <xsl:value-of select="$letterlist" />
>
It should, I think, be the concatenation of the letters.
Mike Kay
Software AG
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