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RE: sorting using a precalculated value
- To: xsl-list at lists dot mulberrytech dot com
- Subject: RE: [xsl] sorting using a precalculated value
- From: Stephane Bailliez <sbailliez at imediation dot com>
- Date: Wed, 28 Mar 2001 16:46:56 +0100
- Reply-To: xsl-list at lists dot mulberrytech dot com
k,
I was ready to build a temporary tree but was wondering if I there was a
cleaner solution.
Thanks for the info.
--
Stéphane Bailliez
Software Engineer, Paris - France
iMediation - http://www.imediation.com
Disclaimer: All the opinions expressed above are mine and not those from my
company.
> -----Original Message-----
> From: Michael Kay [mailto:mhkay@iclway.co.uk]
> Sent: Wednesday, March 28, 2001 5:05 PM
> To: xsl-list@lists.mulberrytech.com
> Subject: RE: [xsl] sorting using a precalculated value
>
>
> You can only sort on a value that you can express using an
> XPath expression.
> There's no scope for using XSLT in the calculation unless you
> either (a) use
> something like saxon:function, or (b) build a temporary tree
> containing the
> calculated sort keys, and then sort that (using the
> node-set() extension).
>
> Mike Kay
>
> > I want to have the following output (ie, class name must be
> > built and the
> > whole stuff sorted)
> >
> > AOuterClass
> > OuterClass1
> > OuterClass1.InnerClass
> >
> >
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list