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Re: Sorting a NodeSet Contained Within a Variable
- To: xsl-list at lists dot mulberrytech dot com
- Subject: Re: [xsl] Sorting a NodeSet Contained Within a Variable
- From: Oliver Becker <obecker at informatik dot hu-berlin dot de>
- Date: Tue, 10 Jul 2001 13:13:36 +0200 (MET DST)
- Reply-To: xsl-list at lists dot mulberrytech dot com
Hi Bryan,
> I have a variable that constitutes a nodeset; is it possible to sort a
> variable nodeset?
Well, you can't sort a node-set because sets are unordered. ;-)
What you can do is to process the nodes of a set in a specific order.
> I ask because I have not been able to get this to work
> (although I can sort nodesets that are not variables).
This isn't different from any other expression that evaluates to a node-set.
Just do either
<xsl:apply-templates select="$set">
<xsl:sort .... />
</xsl:apply-templates>
or
<xsl:for-each select="$set">
<xsl:sort .... />
....
</xsl:for-each>
Hope that helps,
Oliver
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