Re: [xsl] Grouping repeating elements

[tcn at melvaig dot co dot uk (Trevor Nash)]

On Thu, 12 Jul 2001 03:00:37 -0700 (PDT), Till wrote:

>Hi Trevor
>
>thanks for the help.
>
>> So, add a further condition that the <name> node
>> before the one you
>> have found is the same node as the one matched in
>> your template: use
>> preceding-sibling and generate-id().
>
>I managed to create the result tree with:
>
><xsl:copy-of select=".">
><xsl:copy-of
>select="following-sibling"::FirstName[1]/>
><xsl:copy-of select="following-sibling"::Age[1]
>generate-id(prededing-sibling::Name[1])=generate-id(current())]/>
>
Well done.

>Is it possible to apply further templates to the
>result-tree - or do I have to create a new
>xml-document with the result-tree first and then apply
>a second stylesheet to that new document?
>
In standard XSLT, thats your only option. But assuming you want to
process a person at a time, you can put the result inside an
xsl:variable.  Strictly speaking the only thing you can do with this
is copy it unchanged to the result tree, but most processors have a
function like node-set() which you can use like this:

  <xsl:variable name="tree">
        <person>
               <xsl:copy-of ... />
        </person>
  </xsl:variable>
  <xsl:apply-templates select="xx:node-set($tree)" />

The 'xx' depends on your processor - read the docs carefully to see
exaclty what needs to be done here.  Some even let you get away with
  <xsl:apply-templates select="$tree" />
because thats how they think its going to be in the next version of
the XSLT spec.

Hint: because you are going to process the same elements (e.g. age)
again, you may need to use modes.

Regards,
Trevor Nash
--
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