[xsl] Copying into additional attributes from a different part of the tree

["john smith" <john_smith73 at hotmail dot com>]

Given:

<A>
  <B>
    <C id="1" name="CC">
      <D id="2" name="DD"/>
    </C>
  </B>
  <E>
    <F>
      <class>foo</class>
      <NAME>C</NAME>
    </F>
    <F>
      <method>test</method>
      <NAME>C</NAME>
    </F>
    <F>
      <class>foo1</class>
      <NAME>D</NAME>
    </F>
    <F>
      <method>test1</method>
      <NAME>D</NAME>
    </F>
  </E>
</A>


into:

<AA>
    <C id="1" name="CC" class="foo" method="test">
      <D id="2" name="DD" class="foo1" method="test1" />
    </C>
</AA>

The transformation process is as follows:

1. Copy all nodes and attributes of B's descendants
   {in this case, C and D}
   --> At this stage, this is what my result tree will look like:
<AA>
    <C id="1" name="CC">
      <D id="2" name="DD"/>
    </C>
</AA>

2. Look for the NAME attribute in children of E/F and copy the corresponding 
values of class and method names into attributes and add it to the above 
tree: The result will be:

<AA>
    <C id="1" name="CC" class="foo" method="test">
      <D id="2" name="DD" class="foo1" method="test1" />
    </C>
</AA>

I used the <xsl:copy-of> to do step 1...How can I do step 2?

Thanks a lot for the help...


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