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Q: Stripping ns from source tree?
- To: XSL-List at lists dot mulberrytech dot com
- Subject: [xsl] Q: Stripping ns from source tree?
- From: Niclas Olofsson <niclas dot olofsson at ismobile dot com>
- Date: Sun, 26 Aug 2001 20:21:13 +0200
- Reply-To: xsl-list at lists dot mulberrytech dot com
I have a somewhat tricky (for me) question and figured that I might have
missunderstood the way an XSLT processor works with XML namespaces. Read
the FAQ's, specs and all that stuff, but still don't get it.
Basically my problem is that the source tree I'm using have 2 different
namespaces, one for html and one for my own format ("mf").
<?xml version="1.0"?>
<mf:ui xmlns:mf="myformat"
xmlns:html="http://www.w3.org/TR/REC-html40";>
<html:b>
test text
</html:b>
</mf:ui>
Now, when I process this in my stylesheet all the mf nodes are being
transformed to some form of HTML and the HTML should just be put
through. The reason I need namespaces from the beginning is that both
formats share element names (br, p,... etc).
Ok, the expected (whished for) result should be a valid HTML document
(not XHTML) that contains no namespaces (it's all HTML after all). My
stylesheed looks like this.
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:html="http://www.w3.org/TR/REC-html40";
xmlns:mf="myformat"
xmlns="http://www.w3.org/TR/REC-html40";
exclude-result-prefixes="#default html mf"
>
<xsl:output method="html" omit-xml-declaration="yes"/>
<xsl:template match="/">
<HTML>
<BODY>
<xsl:apply-templates/>
</BODY>
</HTML>
</xsl:template>
<xsl:template match="mf:*">
<!-- do nothing right now -->
<xsl:apply-templates/>
</xsl:template>
<xsl:template match="html:*">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Pay attention to the last attribute of the root node. If I understand
this correct this should strip the _result tree_ from all html prefixes.
However, when I copy the HTML elements from the source tree I use
xsl:copy (I could use xsl:copy-of too since no other namespace is nested
inside the html).
Now the result. The processor only strips the nodes constructed inside
the stylesheet, not any of the nodes in the source tree.
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0//EN"
"http://www.w3.org/TR/WD-html-in-xml/DTD/xhtml1-strict.dtd";>
<HTML xmlns="http://www.w3.org/TR/REC-html40";>
<BODY>
<html:b xmlns:html="http://www.w3.org/TR/REC-html40";
xmlns:mf="myformat"> test text </html:b>
</BODY>
</HTML>
I've read up on xsl:copy and it pretty much says so too. But this is not
what I want. I want _all_ namespaces stripped off. I figured I could
match all html: elements and transform them by hand, but I also figured
that approach too be .. hmm, you know, pain in the ass. What I really
would like to do is something like(?)
<xsl:copy exclude-result-prefixes="....">
<xsl:copy-of select="..." exclude-result-prefixes="....">
The question then. How do I get rid of the namespaces?
Cheers,
/Niclas
--
Niclas Olofsson - http://www.ismobile.com
Product Development, isMobile, Aurorum 2, S-977 75 Luleå, Sweden
Phone: +46(0)920-75550
Mobile: +46(0)70-3726404
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