FW: [xsl] xpath expression needed

[William Bagby <williamb at adone dot com>]

I have a very similar issue, except the nodes (in my case attributes) I want
to match doesn't have a definite value.  Let me try to make this clearer.

<level1 name='a' type='1'>
     <field1>value1</field1>
     <field2>some</field2>
     <field3>value3</field3>
</level1>
<level1 name='b' type='1'>
     <field1>value1</field1>
     <field2>some</field2>
     <field3>value3</field3>
</level1>
<level1 name='c' type='2'>
     <field1>value1</field1>
     <field2>someother</field2>
     <field3>value3</field3>
</level1>

I want to match all nodes whose following-sibling::level1 has the same value
for @type.  So in this case, only the first 'level1' node would be matched.

How about:

level1[@type = following-sibling::level1/@type]

Would that work?

-----Original Message-----
From: Sanjay Pandey/Towers Perrin [mailto:pandeys@towers.com]
Sent: Thursday, September 20, 2001 3:14 PM
To: xsl-list@lists.mulberrytech.com
Subject: [xsl] xpath expression needed



Hi List,

I have a XML as follows

<level1 name = 'a'>
     <field1>value1</field1>
     <field2>some</field2>
     <field3>value3</field3>
</level1>
<level1 name='b'>
     <field1>value1</field1>
     <field2>some</field2>
     <field3>value3</field3>
</level1>
<level1 name='c'>
     <field1>value1</field1>
     <field2>someother</field2>
     <field3>value3</field3>
</level1>

I want to get all the occurrences of "field1" whose first following-sibling
"field2" has a value = "some". In this case it should return me 2nodes
(except the last one, where the value would be "someother")

Hope I am clear.

Thanks,
Sanjay



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