[xsl] Re: Unique question

[Dimitre Novatchev <dnovatchev at yahoo dot com>]

Hi Daren,

This is a short solution:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
  <xsl:output method="text"/>
  <xsl:key name="kIndex" match="@index" use="."/>
  <xsl:template match="/">
    <xsl:variable name="x">
       <xsl:for-each select="/*/*/*/*/@index
                          [generate-id()
                          =
                           generate-id(key('kIndex', .)[1])]">
            <xsl:value-of select="'Z'"/>
       </xsl:for-each>
    </xsl:variable>
    
    <xsl:value-of select="string-length($x)"/>
  </xsl:template>
</xsl:stylesheet>

It produces:

4

with the corrected version of your xml source (it was not well-formed):

<groups>
  <group>
    <tables>
      <table index="1" />
      <table index="2" />
    </tables>
    <views>
      <view index="3" />
      <view index="4" />
    </views>
  </group>
  <group>
    <tables>
      <table index="1" />
    </tables>
    <views>
      <view index="1" />
    </views>
  </group>
</groups>

Hope this helped.

Cheers,
Dimitre Novatchev.


Darren Hayduk <dhayduk at nauticusnet dot com> wrote:

I'm trying to take the XPath expression "*/*/@index" and determine how many
unique vales there are - within my current context.
I've tried various axis expressions and can't seem to figure it out... I'd
be happy with either: 
A. the ability to count the unique nodes (and I'll compare to count of all
nodes)
B. just knowing there are duplicates.

Example: Within each group, the table and view indexes need to be unique.
Data in first group is OK, the 'view' in the second group is a duplicate...

<group>
	<tables>
		<table index="1"/>
		<table index="2"/>
	</tables/>		
	<views>
		<view index="3"/>
		<view index="4"/>
	</views/>		
</group>
<group>
	<tables>
		<table index="1"/>
	</tables/>		
	<views>
		<view index="1"/>
	</views/>		
</group>




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