RE: [xsl] populating tables (long)

[Joshua dot Kuswadi at BTFinancialgroup dot com]

Hi Klaus,

I've put this stylesheet together which transforms your given XML doc to produce the expected XML. I hope that this is generic enough for your needs. In particular, when you mention that "the number of levels is not known", I'm hoping that you meant the number of LEVEL_1, LEVEL_2 and/or LEVEL_3 items, not that there is the possibility of LEVEL_4, LEVEL_5 etc

Hope this helps,
Joshua


<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
	<xsl:output method="xml" omit-xml-declaration="yes"/>
	<xsl:template match="/ROOT">
		<table border="1">
			<xsl:apply-templates select="LEVEL_1"/>
		</table>
	</xsl:template>
	
	<xsl:template match="LEVEL_1">
		<tr>
			<td rowspan="{count(LEVEL_2/LEVEL_3)}"><xsl:value-of select="@l1_attr" /></td>
			<td rowspan="{count(LEVEL_2[1]/LEVEL_3)}"><xsl:value-of select="LEVEL_2/@l2_attr" /></td>
			<td rowspan="{count(LEVEL_2[1]/LEVEL_3)}"><xsl:value-of select="LEVEL_2/UNIQUE_LVL_2" /></td>
			<td><xsl:value-of select="LEVEL_2/LEVEL_3/@l3_attr" /></td>
		</tr>
		<xsl:apply-templates select="LEVEL_2[1]/LEVEL_3[position() != 1]" />
		<xsl:apply-templates select="LEVEL_2[position() != 1]" />
	</xsl:template>
	
	<xsl:template match="LEVEL_2">
		<tr>
			<td rowspan="{count(LEVEL_3)}"><xsl:value-of select="@l2_attr" /></td>
			<td rowspan="{count(LEVEL_3)}"><xsl:value-of select="UNIQUE_LVL_2" /></td>
			<td><xsl:value-of select="LEVEL_3/@l3_attr" /></td>
		</tr>
		<xsl:apply-templates select="LEVEL_3[position() != 1]" />
	</xsl:template>
	
	<xsl:template match="LEVEL_3">
		<tr>
			<td><xsl:value-of select="@l3_attr"/></td>
		</tr>
	</xsl:template>
</xsl:stylesheet>

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