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arguments for xsl:call-template
- From: "Charly" <cohana at investacorp dot com>
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Fri, 7 Dec 2001 09:38:42 -0800
- Subject: [xsl] arguments for xsl:call-template
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi everyone.
I'm a beginner with XSL .
Does anyone of you has any idea how to call a template and passing with a
node as argument.
I'm trying the following .
<xsl:template name="histogram">
<xsl:param name="path" />
<xsl:for-each select="$path">
<xsl:value-of select="@value"/>
</xsl:for-each>
</xsl:template>
<xsl:call-template name="histogram">
<xsl:with-param name="path" select="'/report/histo/bar'" />
</xsl:call-template>
my XML looks like .
<report>
<histo>
<bar value="20" />
<bar value="30" />
<bar value="40" />
<bar value="50" />
</histo>
</report>
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