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Re: for-each order
Nope,
That doesn't do it .
----- Original Message -----
From: "Long Zhao" <LZhao@firstgenetic.net>
To: <xsl-list@lists.mulberrytech.com>
Sent: Friday, December 14, 2001 9:34 AM
Subject: RE: [xsl] for-each order
> how about this
>
> <xsl:variable name="position">
> <xsl:for-each select="$path">
> <xsl:value-of select="concat(@value, position)"/>,
> </xsl:for-each>
> </xsl:variable>
>
> Long
>
> -----Original Message-----
> From: Charly [mailto:cohana@investacorp.com]
> Sent: Friday, December 14, 2001 2:35 PM
> To: xsl-list@lists.mulberrytech.com
> Subject: [xsl] for-each order
>
>
> Hello,
> Is there a way to do <xsl:for-each ..... and looping backwards.
>
> My XML looks like
> <histo>
> <bar value="60" legend="Jan" />
> <bar value="77" legend="Feb" />
> <bar value="53" legend="Mar" />
> <bar value="14" legend="Apr" />
> </histo>
>
> and I want to store 14,53,77,60 in a variable .
>
>
> <xsl:variable name="position">
> <xsl:for-each select="$path">
> <xsl:value-of select="@value"/>,
> </xsl:for-each>
> </xsl:variable>
>
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
> XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
>
>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list