Re: [xsl] Singling Out Nodes in Look-up Table

[Jeni Tennison <jeni at jenitennison dot com>]

Hi Chuck,

> I can get close with the key I'm using, which gives me the node set
> I'm after, but I really need to map each node within that set, so
> that instead of this statement:
>
> <xsl:value-of select="$lookup/@id"/>
>
> getting only the first node of the node set, I need a better
> statement that iterates through the set. An apply-templates gets me
> the whole set, instead of individual nodes, which makes sense to me.
> These are truncated source docs -- the full docs would reveal that
> the key exposes large node sets consisting of several id="xxxxxx"
> attribute value pairs.

I think I'm missing something about what you're trying to do. Can't
you either use xsl:for-each:

  <xsl:for-each select="$lookup">
    <xsl:value-of select="@id" />
    <xsl:text>&#xA;</xsl:text>
  </xsl:for-each>

or xsl:apply-templates:

  <xsl:apply-templates select="$lookup" />

with a template matching row elements:

<xsl:template match="row">
    <xsl:value-of select="@id" />
    <xsl:text>&#xA;</xsl:text>
</xsl:template>


By the way, since what you actually want to get are the field elements
whose name is 'Position', based on their value, a better key might be:

<xsl:key name="lookup" match="field[@name = 'Position']" use="."/>

Then instead of using:

  <xsl:variable name="lookup"
    select="key('lookup', $position)/field[@name='Position']"/>

You could just do:

  <xsl:variable name="lookup" select="key('lookup', $position)" />
    
Cheers,

Jeni

---
Jeni Tennison
http://www.jenitennison.com/


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