[xsl] collapsing consecutive elements

[Saverio Perugini <sperugin at csgrad dot cs dot vt dot edu>]

Hello,

Does anyone know of a quick and dirty way to collapse a series of
elements which each have only one child?

For example, I'd like to transform the following XML

<db>
   <a>
      <b>
         <c>
            <d/>
            <e/>
         </c>
      </b>
   </a>

   <f>
      <g>
         <h>
            <i/>
            <j/>
         </h>
      </g>
   </f>
</db>

into

<db>
    <a_b_c>
       <d/>
       <e/>
    </a_b_c>

    <f_g_h>
       <i/>
       <j/>
    </f_g_h>
</db>

The following stylesheet is close, but not quite there yet.

<?xml version='1.0'?>

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                version="1.0">

<xsl:output method="xml"/>

<xsl:template match="node()[child::node()]" priority="0.7">

   <xsl:if test="count(child::node()) = 1">
      <xsl:element name='{local-name()}___{local-name(child::node())}'>
      <xsl:apply-templates/>
      </xsl:element>
   </xsl:if>

   <xsl:if test="local-name() != 'db' and count(child::node()) > 1 and count(preceding-sibling::node()) = 0 and count(following-sibling::node()) = 0">
      <xsl:apply-templates/>
   </xsl:if>

   <xsl:if test="count(child::node()) > 1 and (count(preceding-sibling::node()) > 0 or count(following-sibling::node()) > 0)">

      <xsl:copy>
         <xsl:apply-templates/>
      </xsl:copy>
   </xsl:if>

   <xsl:if test="local-name() = 'db'">
      <xsl:copy>
         <xsl:apply-templates/>
      </xsl:copy>
   </xsl:if>

</xsl:template>

<xsl:template match="@* | node()" priority="0.6">

   <xsl:copy>
      <xsl:apply-templates select="@* | node()"/>
   </xsl:copy>

</xsl:template>

</xsl:stylesheet>

Many Thanks,

Saverio Perugini


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