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Re: collapsing consecutive elements
- From: "G. Ken Holman" <gkholman at CraneSoftwrights dot com>
- To: XSL-List at lists dot mulberrytech dot com
- Date: Fri, 18 Jan 2002 13:45:20 -0500
- Subject: Re: [xsl] collapsing consecutive elements
- Reply-to: xsl-list at lists dot mulberrytech dot com
At 2002-01-18 12:50 -0500, Saverio Perugini wrote:
>Does anyone know of a quick and dirty way to collapse a series of
>elements which each have only one child?
>...
>The following stylesheet is close, but not quite there yet.
You will find the example below shorter than your intermediate answer.
I hope this helps.
............. Ken
T:\ftemp>type saverio.xml
<db>
<a>
<b>
<c>
<d/>
<e/>
</c>
</b>
</a>
<f>
<g>
<h>
<i/>
<j/>
</h>
</g>
</f>
</db>
T:\ftemp>type saverio.xsl
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output indent="yes"/>
<xsl:template match="*">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[count(*)=1]"><!--first with one child-->
<xsl:apply-templates mode="one-child"/>
</xsl:template>
<!--child of last one with one child-->
<xsl:template match="*[count(*)!=1]" mode="one-child">
<xsl:variable name="container-name">
<xsl:for-each select=".|ancestor::*[count(*)=1]">
<xsl:if test="position()>1">_</xsl:if>
<xsl:value-of select="name(.)"/>
</xsl:for-each>
</xsl:variable>
<xsl:element name="{$container-name}">
<xsl:apply-templates/>
</xsl:element>
</xsl:template>
<xsl:template match="text()" mode="one-child"/>
</xsl:stylesheet>
T:\ftemp>saxon saverio.xml saverio.xsl
<?xml version="1.0" encoding="utf-8"?>
<db>
<a_b_c>
<d/>
<e/>
</a_b_c>
<f_g_h>
<i/>
<j/>
</f_g_h>
</db>
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