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Re: commandline parameters
- From: Joerg Heinicke <joerg dot heinicke at gmx dot de>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Tue, 19 Mar 2002 11:12:06 +0100
- Subject: Re: [xsl] commandline parameters
- References: <F204QBKetI6KB06QNMp00009bbe@hotmail.com>
- Reply-to: xsl-list at lists dot mulberrytech dot com
On the page http://xml.apache.org/xalan-j/commandline.html you can see
the correct syntax:
java org.apache.xalan.xslt.Process -IN foo.xml -XSL foo.xsl -OUT foo.out
-PARAM name value
In your stylesheet you have to set a top-level-param:
> <?xml version="1.0"?>
> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="commandparam" value="'default'"/>
> <xsl:template match="/">
You don't need <xsl:param> here.
> <xsl:value-of select="$commandparam"/>
> </xsl:template>
> </xsl:stylesheet>
>
>
> My questions are:
> 1. If i want to read the parameter through -PARAM, is the above xsl
> correct?
> 2. what would be the command that runs in the commandline to pass on the
> parameter. would it be something like this..
> java org.apache.xalan.xslt.Process -IN commandlineexp.xml
> -XSL commandlineexp.xsl -OUT multi -PARAM commandparam commandparamvalue?
>
> please let me know if i am wrong and in that case the correct syntax of
> the commandline statement and the xsl structure
> laura
Regards,
Joerg
--
System Development
VIRBUS AG
Fon +49(0)341-979-7411
Fax +49(0)341-979-7409
joerg.heinicke@virbus.de
www.virbus.de
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