This is the mail archive of the xsl-list@mulberrytech.com mailing list .


Index Nav: [Date Index] [Subject Index] [Author Index] [Thread Index]
Message Nav: [Date Prev] [Date Next] [Thread Prev] [Thread Next]
Other format: [Raw text]

Re: Ignoring default attributes during XSL transform


As far as I know, the default value (from DTD) of attributes are added 
by the parser (please correct me if I'm wrong). So when the stylesheet 
gets the document, every attribute is in the XML tree. But the 
stylesheet knows nothing about whether it's a default value - the 
attribute is in the tree, not more, not less.

Regards,

Joerg

Manny Parasirakis wrote:
> My follow on question is whether or not there is a way to compare an 
> attribute value to its default value defined in the DTD?
> 
> At 10:02 PM 4/17/2002 +0200, Joerg Heinicke wrote:
> 
>> <xsl:apply-templates select="* | @*[. != '']">
>>
>> Regards,
>>
>> Joerg
>>
>> Manny Parasirakis wrote:
>>
>>> I am trying to figure out how I can ignore outputting attributes 
>>> whose values are not set (=""). I am fairly new at this but cannot 
>>> figure it out. I need to do this for all XML tags. Here is my XSL:
>>> <xsl:template match="*|@*">
>>>         <xsl:copy>
>>>                 <xsl:apply-templates select="*|@*"/>
>>>         </xsl:copy>
>>> </xsl:template>
>>> I've tried a bunch of things but cannot figure this out.

-- 

System Development
VIRBUS AG
Fon  +49(0)341-979-7419
Fax  +49(0)341-979-7409
joerg.heinicke@virbus.de
www.virbus.de


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list


Index Nav: [Date Index] [Subject Index] [Author Index] [Thread Index]
Message Nav: [Date Prev] [Date Next] [Thread Prev] [Thread Next]