[xsl] Sorting XML with XSL, output as XML

[Ernst Wolthaus <ernst dot wolthaus at cmg dot nl>]

Hi all,

I'm new it this so I hope I'm posting this message the right way. 
Anyway...

I've got a HTML-pager with a table, with a data island, so the XML data 
is bounded in the table by Datafld and Datasrc. Now I want to sort the 
XML-data by an XSL-file and a XSL:SORT command. However, this needs to 
be generic so I can use the same XSL for all kinds of XML, because else 
I have to make a XSL for every XML.

Example:
	<?xml version="1.0"?>
	<book>
	<chapter>
	<number>2</number>
	<title>two</title>
	<paragraph>text 2</paragraph>
	</chapter>
	<chapter>
	<number>1</number>
	<title>one</title>
	<paragraph>text 1</paragraph>
	</chapter>
	</book>

How do I sort this data by e.g. Number or by Title in a generic way. It's 
needs to output the "same" XML but sorted like:

	<?xml version="1.0"?>
	<book>
	<chapter>
	<number>1</number>
	<title>one</title>
	<paragraph>text 1</paragraph>
	</chapter>
	<chapter>
	<number>2</number>
	<title>two</title>
	<paragraph>text 2</paragraph>
	</chapter>
	</book>

I know how to sort with xsl:param and <xsl:sort 
select="@*[name()=$sortfield]" order="{$sortorder}" /> but how do I get 
the XML back like the XML described above...???

I've spend a lot of this on this so I would greatly appreciate any 
help!!

Thanks,
Ernst Wolthaus

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