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Re: How can a template match elements created by xsl?????
- From: ChivaBaba at aol dot com
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Thu, 16 May 2002 05:12:44 EDT
- Subject: Re: [xsl] How can a template match elements created by xsl?????
- Reply-to: xsl-list at lists dot mulberrytech dot com
J.Pietschmann wrote:
>If this still doesn't fix your problem, check whether
> you have set a default namespace for the style sheet.
You was right again, it was a namespace-problem. as you see, I defined a default namespace:
++++++++++++++++++++++++++++++++++++++++++++++++++++++++
<xsl:stylesheet version="1.1"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:exsl="http://exslt.org/common"
extension-element-prefixes="exsl"
xmlns="http://www.w3.org/TR/REC-html40">
++++++++++++++++++++++++++++++++++++++++++++++++++++++++
Following your advice to check the variable with copy-of I realized that 'tool' belongs to the "html"-namespace.
I fixed the problem by creating " <tool xmlns=""> " instead of " <tool> " and now the template matches what I want.
But by checking the output I get now, I realized that the double sort you sent me some mails ago does not work right.
++++++++++++++++++++++++++++++++++++++++++++++++++++++++
<xsl:variable name="sw">
<xsl:for-each select="exsl:node-set($tools)">
<xsl:sort data-type="text" lang="en" select="@category"/>
<xsl:sort data-type="text" lang="en" select="@name"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:variable>
++++++++++++++++++++++++++++++++++++++++++++++++++++++++
My tools in $tools are only sorted by category but not by name!!
What could the problem with this sort-instruction be????
Many Thanks and much respect,
Stefan.
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