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Re: basic xpath question
- From: Jeni Tennison <jeni at jenitennison dot com>
- To: "Hanlan, Dominic - Senior Developer" <dhanlan at icc dot co dot uk>
- Cc: "'XSL-List at lists dot mulberrytech dot com'" <XSL-List at lists dot mulberrytech dot com>
- Date: Thu, 20 Jun 2002 10:32:27 +0100
- Subject: Re: [xsl] basic xpath question
- Organization: Jeni Tennison Consulting Ltd
- References: <CAE1286F75E7324F872106110D9DC409C1D11E@Hampton-exch>
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi Dominic,
> I have an xml document to be styled, if I have a construct such as
>
> <section id="para">this is text <section id="url"
> url="http://xx.yy.zz">which is to be a link</section></section>
>
> How do I, in xslt, recognise the "url" tag within the "para" tag,
> such that I could ouput someting like
>
> <p>this is test <a href="http://xx.yy.zz">which is to be a link</a></p>
The simplest way would be to use templates that match section elements
with different values for their id attributes:
<xsl:template match="section[@id = 'para']">
<p><xsl:apply-templates /></p>
</xsl:template>
<xsl:template match="section[@id = 'url']">
<a href="{@url}"><xsl:apply-templates /></a>
</xsl:template>
Cheers,
Jeni
---
Jeni Tennison
http://www.jenitennison.com/
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