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Finding out the existence of a node
- From: "Kalyan Kumar Mudumbai" <kalyan_tech at rediffmail dot com>
- To: XSL-List at lists dot mulberrytech dot com
- Date: 1 Jul 2002 10:49:48 -0000
- Subject: [xsl] Finding out the existence of a node
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi,
is there a way to find out if a particular node exists in an
xml file or not?
For example, I have an xml file which has a node <MyName>, how can
I know if the same node is also present in another xml file which
the stylesheet is processing?
<xsl:variable name="node_name" select="local-name()"/>
gives me the name of the node into the variable node_name.
<xsl:param name="source" select="./Doc.xml"/>
gives selects the path of Doc.xml into $source
Now how do I know whether $node_name is present in Doc.xml or not?
Please help me out.
Thanks,
Kalyan
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