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RE: Grouping on multiple nested elements
- From: Jarno dot Elovirta at nokia dot com
- To: <xsl-list at lists dot mulberrytech dot com>
- Date: Tue, 16 Jul 2002 11:06:23 +0300
- Subject: RE: [xsl] Grouping on multiple nested elements
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hi,
> I have no problem grouping by program_name using the
> Muenchian method -
> there is only one program_name for each story. However,
> grouping by subject
> has me stumped - do I need multiple keys and how do I keep
> track of the
> current subject?
Did you mean
<xsl:key name="story" match="story" use="subjects/subject" />
<xsl:key name="subject" match="subject" use="." />
<xsl:template match="data">
<xsl:for-each select="story/subjects/subject[generate-id() = generate-id(key('subject', .))]">
<xsl:sort select="." />
<xsl:value-of select="." />
<xsl:text>

</xsl:text>
<xsl:for-each select="key('story', .)">
<xsl:text> </xsl:text>
<xsl:value-of select="story_title" />
<xsl:text>
 </xsl:text>
<xsl:value-of select="description" />
<xsl:text>

</xsl:text>
</xsl:for-each>
</xsl:for-each>
</xsl:template>
"Launch auto-documentation daemon" and all that,
Santtu
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