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Dimitre's is more generic. What if you want to replace more than one element? Joerg Vasu Chakkera wrote:
Hi Mike, Use the identity templates plus an additional one matching the element that is to be renamed: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" omit-xml-declaration="yes"/> <xsl:template match="/ | @* | node()"> <xsl:copy> <xsl:apply-templates select="@* | node()"/> </xsl:copy> </xsl:template> <xsl:template match="PolicyPeriod"> <com.castek.insure3.customer.businessobjects.PolicyPeriod> <xsl:apply-templates select="@* | node()"/> </com.castek.insure3.customer.businessobjects.PolicyPeriod> </xsl:template> </xsl:stylesheet>
... wouldnt the following do the job??
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="PolicyPeriod">
<com.castek.insure3.customer.businessobjects.PolicyPeriod>
<xsl:copy-of select="node()"/>
</com.castek.insure3.customer.businessobjects.PolicyPeriod>
</xsl:template>
</xsl:stylesheet>
vasu
-- System Development VIRBUS AG Fon +49(0)341-979-7419 Fax +49(0)341-979-7409 joerg.heinicke@virbus.de www.virbus.de XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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