Re: [xsl] XPath selection using //

["Vasu Chakkera" <vasucv at hotmail dot com>]

Hi Filipe,

The XML you given is not wellformed...
and if you want to evaluate only m elements you can write a template that 
matches the m element
<xsl:template match="m">
and if you want to find the next m element's a attribute,you shud use
following::m/@a..
your following-sibling wont work because the next 'm' is not actually a 
sibling of the first 'm'.

i reckon you go through Mike Kay's XSLT Reference to understand how axis 
works.
hope this helps
Vasu


> From: "Filipe Correia" <filipe.correia@paradigmaxis.pt>
> Reply-To: xsl-list@lists.mulberrytech.com
> To: xsl-list@lists.mulberrytech.com
> Subject: [xsl] XPath selection using //
> Date: Wed, 17 Jul 2002 15:11:06 +0100
>
>
>   Hi,
>
> Here's a tree wich is a part of my xml document:
>
> <b>
>   <m a="attribute">
>     text text text
>     <t>
>       <r>
>         <d>more text</d>
>       <r/>
>     </t>
>   </m>
>   <t>
>     <r>
>       <d/>
>       <d><m a="attribute">text</m></d>
>     <r/>
>   </t>
>   <m/>
>   text
> </b>
>
> what I want to do is to evaluate only the
> contents of the "m" elements. For each "m"
> element I also need to output the next "m"'s
> "a" atribute.
> Everything else should be ignored.
>
> In the stylesheet that I use I'm applying the
> respective templates like this:
>
>    ...
>
>    <xsl:apply-templates select="b//m"/>
>
>    ...
>
>  using the following template to apply
>  templates to all descendants of the
>  current "m" node and to get the next "m"'s
>  "a" atribute:
>
>    <xsl:template match="m">
> 	<xsl:apply-templates/>
>       Atribute a of the following m is:
>       <xsl:value-of 
> select="ancestor::*[parent::b]/following-sibling::node()//m/@a"/>
>    </xsl:template>
>
>  but getting the next "m"'s "a" atribute is
>  not working as I expected...
>
>  Any idea on what I may be doing wrong?
>
>
>      Thanks in advance,
>
>        Filipe
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



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