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Re: transformation does happen after copy-of?
- From: David Carlisle <davidc at nag dot co dot uk>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Tue, 23 Jul 2002 11:25:03 +0100
- Subject: Re: [xsl] transformation does happen after copy-of?
- References: <000301c2322e$f36b5fe0$ccf2a8c0@DTVISEU.PGT>
- Reply-to: xsl-list at lists dot mulberrytech dot com
> I supose that the attribute nodes does't get selected in the node()
> function
node() isn't a function, it is a node test, like text().
attribute nodes are matched by node() but
select="node()" is short for
select="child::node()"
and attribute nodes are not child nodes of any node.
> so, when you do a match="node()" you are selecting all nodes
> except attribute nodes, b
no node() does match attribute nodes.
> but these also have text nodes (that contain
> there values) and these are selected by the match="node()"
attribute nodes do not have any children. The value of an attribute i
not a text node.
david
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