RE: [xsl] transformation does happen after copy-of?

["Andrew Welch" <awelch at piper-group dot com>]

DC:
>but match=node() matches those nodes for which there exists some other
>node such that $x//node() selects a node set that includes the node you
>are trying to match. attributes are never in //

This sounds just like how my lecturers used to convey meaning...

...or possibly the way techies speak their managers when they need some
more time ;)

cheers
andrew



-----Original Message-----
From: David Carlisle [mailto:davidc@nag.co.uk]
Sent: 23 July 2002 13:35
To: xsl-list@lists.mulberrytech.com
Subject: Re: [xsl] transformation does happen after copy-of?




> <xsl:template match="node()">
> 
> Which you can't - what am I missing?

the fact that in a match, as in a select a step without an explicit axis
is an abbreviated child axis.

a node test node() will be true for an attribute node, which is why
attribute::node() is true (but equivalent to @* so not usually written).

but match=node() matches those nodes for which there exists some other
node such that $x//node() selects a node set that includes the node you
are trying to match. attributes are never in //

David


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