RE: [xsl] merge tree structure with no redundancy

["McNally, David" <David dot McNally at moodys dot com>]

BTW, I typed the wrong copy of subscriber.xml.  It should be (note the
corrected id element):

<?xml version="1.0" encoding="ISO-8859-1"?>
<a>
  <subscribers>
    <subscriber>
      <id id="1"/>
      <path>
        <node type="T1" name="N1">
          <node type="T2" name="N2">
            <node type="T3" name="N3"/>
          </node>
        </node>
      </path>
    </subscriber>
    <subscriber>
      <id id="2"/>
      <path>
        <node type="T1" name="N1">
          <node type="T2" name="N2">
            <node type="T3" name="N4"/>
          </node>
        </node>
      </path>
    </subscriber>
  </subscribers>
</a>

David.

> -----Original Message-----
> From: McNally, David 
> Sent: Friday, August 02, 2002 1:11 PM
> To: 'xsl-list@lists.mulberrytech.com'
> Subject: RE: [xsl] merge tree structure with no redundancy
> 
> 
> When in doubt, reach for keys and the Meunchian technique, both well
> described in the faq.
> 
> Basically you need two keys - "me" which is used to figure 
> out whether each
> node is the first, in document order, with a particular @type 
> and @name
> pair.  The second, "parent", is used to process all the nodes who are
> children of a particular @type and @name pair, regardless of 
> where they are
> in the file.  So basically the node template decides if the 
> node is the
> first with its type/name - if it isn't it does nothing.  If it is, it
> outputs the element and attributes, and then applies 
> templates to all nodes
> that are "children" of that node, based on the "parent" key.
> 
> I think this works properly, but handle with care...
> 
> <?xml version="1.0" encoding="UTF-8"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
> 	<xsl:output method="xml" version="1.0" encoding="UTF-8"
> indent="yes"/>
> 
> <xsl:key name="parent" match="node"
> use="concat(parent::node/@type,'::',parent::node/@name)"/>
> <xsl:key name="me" match="node" use="concat(@type,'::',@name)"/>
> 
> <xsl:template match="a">
> <a>
> 	<xsl:apply-templates select="subscribers/subscriber/path/node"/>
> </a>
> </xsl:template>
> 
> <xsl:template match="node">
> 	<xsl:variable name="mykey" select="concat(@type,'::',@name)"/>
> 	<xsl:choose>
> 		<xsl:when test="generate-id(.) =
> generate-id(key('me',$mykey)[1])">
> 			<xsl:element name="{name()}">
> 				<xsl:copy-of select="@*"/>
> 				<xsl:if test="not(node)">
> 					<xsl:attribute name="id">
> 						<xsl:value-of
> select="ancestor::subscriber/id/@id"/>
> 					</xsl:attribute>
> 				</xsl:if>
> 				<xsl:apply-templates
> select="key('parent',concat(@type,'::',@name))"/>
> 			</xsl:element>
> 		</xsl:when>
> 	</xsl:choose>
> </xsl:template>
> 
> </xsl:stylesheet>
> 
[snip]


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