RE: [xsl] continuation of xsl:number

["Andrew Welch" <awelch at piper-group dot com>]

To answer my own question (too quick to post ;)

  <xsl:value-of select="count(preceding::step1|.)"/>
  <xsl:if test="local-name()='step2'">
    <xsl:number level="multiple" format=".1.1" 
         count="step2|step3|step4|step5"/>
  </xsl:if>

cheers
andrew


> -----Original Message-----
> From: Andrew Welch 
> Sent: 21 August 2002 12:19
> To: xsl-list@lists.mulberrytech.com
> Subject: [xsl] continuation of xsl:number
> 
> 
> 
> Hi all,
> 
> The data I have contains many nested steps, both in say <start> and
> <end>.  To number these steps I use xsl:number - however 
> because of the
> doc structure <steps> in <end> start from 1 again (as it 
> should), but I
> need it to continue counting from the last step:
> 
> <root>
>   <start>
>     <s1>
>       <para>1</para>
>       <s2>
>         <para>1.1</para>
>       </s2>
>     </s1>
>     <s1>
>       <para>2</para>
>     </s1>
>   </start>
>   <end>
>     <s1>
>       <para>3</para>
>       <s2>3.1....</s2>
>     </s1>
>   </end>
> </root> 
> 
> As in the example, the numbering of the steps in the end 
> should carry on
> from the last step.
> 
> Is the only way to use count() instead of some neat use of 
> xsl:number??
> (they could go 9 steps deep so it would be quite a line of code...)
> 
> cheers
> andrew
> 
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