Re: [xsl] getting distinct content from list (?)

["Vasu Chakkera" <vasucv at hotmail dot com>]

Kurt,
Your Problem is simple but without you providing the XML file, nothing much 
can be done.can you please send a snip.. of your xml so that its easu to 
sort your  problem.
Vasu
> From: Kurt George Gjerde <kurt.gjerde@intermedia.uib.no>
> Reply-To: xsl-list@lists.mulberrytech.com
> To: <xsl-list@lists.mulberrytech.com>
> Subject: [xsl] getting distinct content from list (?)
> Date: Thu, 22 Aug 2002 16:31:10 +0200 (MET DST)
>
> Hi,
>
> The least of my xslt problems at the moment is this one (I have others
> which I'm sure I'll come back to ;). This is probably easy
> but I just can't see it. Here it goes.
>
> I have an xpath which results in a list like:
> 'cynthia', 'bob', 'janet', 'bob', 'jack', 'bob', 'jack'.
>
> These are user IDs collected from different locations in a document. The
> actual xpath is:
>   notify/@user |
>   /ming/users/user[@global-notify='yes']/@id |
>   /ming/client[@id=$myClient]/admin/@user
>
> I need to output this as: "bob, cynthia, jack and janet".
> Without the duplicates (sorted and xslt 1.0).
>
> How?
>
>
> Thanks,
> -Kurt.
> __________
> kurt george gjerde <kurt.gjerde@intermedia.uib.no>
> intermedia uib, university of bergen
>
> Free Jon - http://www.efn.no/freejon01-2002.html
>
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



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