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Re: My Difficult counting problem
- From: Mike Brown <mike at skew dot org>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Thu, 22 Aug 2002 16:22:49 -0600 (MDT)
- Subject: Re: [xsl] My Difficult counting problem
- Reply-to: xsl-list at lists dot mulberrytech dot com
Girard Tim-TGIRARD1 wrote:
> hello,
>
> I need some help doing the following, I can't seem to figure out how to do
> this in XSL
>
> I need to convert something like this
> <myElement>
> <foo name="foobar1"/>
> <foo name="foobar2"/>
> <foo name="foobar1"/>
> <foo name="foobar3"/>
> <foo name="foobar1"/>
> <foo name="foobar1"/>
> <foo name="foobar3"/>
> </myElement>
>
> and the output after running it through the XSL would be
>
> numberOccurrences[] = {1, 1, 2, 1, 3, 4, 2};
>
> basically for each foo with a duplicate name you put the occurrence number
> of it in the array at the correct position.
<xsl:template match="myElement">
<xsl:text>numberOccurrences[] = {</xsl:text>
<xsl:for-each select="foo">
<xsl:value-of select="count(preceding-sibling::foo[@name=current()/@name])+1"/>
<xsl:if test="position() != last()">, </xsl:if>
</xsl:for-each>
<xsl:text>};</xsl:text>
</xsl:template>
If efficiency is an issue, xsl:key may be of some utility; it would be easy to
set up a key that does the same work as the preceding-sibling business.
- Mike
____________________________________________________________________________
mike j. brown | xml/xslt: http://skew.org/xml/
denver/boulder, colorado, usa | resume: http://skew.org/~mike/resume/
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