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Returning the file name of the input file
- From: Cams Ismael <Ismael dot Cams at siemens dot atea dot be>
- To: XSL-List at lists dot mulberrytech dot com
- Date: Wed, 28 Aug 2002 09:35:36 +0200
- Subject: [xsl] Returning the file name of the input file
- Reply-to: xsl-list at lists dot mulberrytech dot com
Hello,
does anybody if the following is possible:
I want to use the name of the inputfile in the outputfile. So if I want to
transform the file c:\temp\test.xml, I want to get in my output
c:\temp\test.xml.
I am afraid there is no method to do this, but if anybody knows a solution I
will be very thankfull for that.
kind regards,
Ismaël
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