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Re: Node selection based on parent attribute
- From: David Carlisle <davidc at nag dot co dot uk>
- To: xsl-list at lists dot mulberrytech dot com
- Date: Fri, 30 Aug 2002 15:29:16 +0100
- Subject: Re: [xsl] Node selection based on parent attribute
- References: <F235x23prOPN5n5sKAo00020f4a@hotmail.com>
- Reply-to: xsl-list at lists dot mulberrytech dot com
> passing through a parameter of 1 using:
when the param is 1 control passes first to the tree template...
<xsl:template match="tree">
<xsl:apply-templates select="menu"/>
</xsl:template>
so now the current node list is all the menu elements of tree,
so first the control passes to the menu template, with the current node
being the first menu (which has id=1).
<xsl:template match="menu">
<xsl:for-each select="menu[@id=$id]/menu">
<xsl:value-of select="@id"/>
</xsl:for-each>
</xsl:template>
This selects all the menu children of the current node which have id=1.
there are no such children so nothing is returned.
i think that what you want might be
<xsl:template match="tree">
<xsl:apply-templates select="menu[@id=$id]/menu"/>
</xsl:template>
<xsl:template match="menu">
<xsl:value-of select="@id"/>
</xsl:template>
David
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